sqlserver 统计sql语句大全收藏

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1.计算每个人的总成绩并排名 select name,sum(score) as allscore from stuscore group by name order by allscore 2.计算每个人的总成绩并排名 select distinct t1.name,t1.stuid,t2.allscore from stuscore t1,( select stuid,sum(score) as allscore from stuscore group by stuid)t2where t1.stuid=t2.stuidorder by t2.allscore desc 3. 计算每个人单科的最高成绩 select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,(select stuid,max(score) as maxscore from stuscore group by stuid) t2where t1.stuid=t2.stuid and t1.score=t2.maxscore 4.计算每个人的平均成绩 select distinct t1.stuid,t1.name,t2.avgscore from stuscore t1,(select stuid,avg(score) as avgscore from stuscore group by stuid) t2where t1.stuid=t2.stuid 5.列出各门课程成绩最好的学生 select t1.stuid,t1.name,t1.subject,t2.maxscore from stuscore t1,(select subject,max(score) as maxscore from stuscore group by subject) t2where t1.subject=t2.subject and t1.score=t2.maxscore 6.列出各门课程成绩最好的两位学生 select distinct t1.* from stuscore t1 where t1.id in (select top 2 stuscore.id from stuscore where subject = t1.subject order by score desc) order by t1.subject 7.学号姓名语文数学英语总分平均分 select stuid as 学号,name as 姓名,sum(case when subject='语文' then score else 0 end) as 语文,sum(case when subject='数学' then score else 0 end) as 数学,sum(case when subject='英语' then score else 0 end) as 英语,sum(score) as 总分,(sum(score)/count(*)) as 平均分from stuscoregroup by stuid,name order by 总分desc 8.列出各门课程的平均成绩 select subject,avg(score) as avgscore from stuscoregroup by subject 9.列出数学成绩的排名 declare @tmp table(pm int,name varchar(),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score descdeclare @id intset @id=0;update @tmp set @id=@id+1,pm=@idselect * from @tmp select DENSE_RANK () OVER(order by score desc) as row,name,subject,score,stuid from stuscore where subject='数学'order by score desc . 列出数学成绩在2-3名的学生 select t3.* from(select top 2 t2.* from (select top 3 name,subject,score,stuid from stuscore where subject='数学'order by score desc) t2 order by t2.score) t3 order by t3.score desc . 求出李四的数学成绩的排名 declare @tmp table(pm int,name varchar(),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score descdeclare @id intset @id=0;update @tmp set @id=@id+1,pm=@idselect * from @tmp where name='李四' . 课程不及格（-）良（-）优（-） select subject, (select count(*) from stuscore where score< and subject=t1.subject) as 不及格,(select count(*) from stuscore where score between and and subject=t1.subject) as 良,(select count(*) from stuscore where score > and subject=t1.subject) as 优from stuscore t1 group by subject . 数学:张三(分),李四(分),王五(分),赵六(分) declare @s varchar()set @s=''select @s =@s+','+name+'('+convert(varchar(),score)+'分)' from stuscore where subject='数学' set @s=stuff(@s,1,1,'')print '数学:'+@s

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